MDN content lives on GitHub as Markdown. Fetching the raw Markdown is more compact than rendering the SPA page.
- English (
en-US): https://github.com/mdn/content - Other locales (
ja,fr,zh-CN, ...): https://github.com/mdn/translated-content
Steps
1. Map the URL to a content path
From https://developer.mozilla.org/{locale}/docs/{path}:
# en-US
https://raw.githubusercontent.com/mdn/content/main/files/en-us/{path-lowercased}/index.md
Examples:
| MDN URL | Source path |
|---|---|
| `developer.mozilla.org/en-US/docs/Web/API/Fetch_API/Using_Fetch` | `mdn/content` → `files/en-us/web/api/fetch_api/using_fetch/index.md` |
| `developer.mozilla.org/ja/docs/Web/JavaScript/Reference/Global_Objects/Array` | `mdn/translated-content` → `files/ja/web/javascript/reference/global_objects/array/index.md` |
If the original MDN URL redirects (visible by following with `curl -IL`), resolve it before mapping.
### 2. Fetch the Markdown
```bash
# en-US
curl -s -o /tmp/mdn.md \
"https://raw.githubusercontent.com/mdn/content/main/files/en-us/{path}/index.md"
# Translated
curl -s -o /tmp/mdn.md \
"https://raw.githubusercontent.com/mdn/translated-content/main/files/{locale}/{path}/index.md"
3. Read the file
Read /tmp/mdn.md
If the path is wrong (404), fall back to WebFetch on the original developer.mozilla.org URL.
License / attribution
MDN content is dual-licensed (CC BY-SA 2.5 for prose, CC0 for code samples). When quoting, link back to the MDN page.
Reference
- MDN content repo (en-US): https://github.com/mdn/content
- Translated content: https://github.com/mdn/translated-content
- License: https://github.com/mdn/content/blob/main/LICENSE.md